23. Construct a Triangle Given Two Sides and the Inradius
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This Demonstration draws a triangle given two side lengths and and the inradius (the radius of the inscribed circle). This construction involves solving a cubic and is not possible with a ruler and compass.
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Contributed by: Izidor Hafner (November 2017)
Open content licensed under CC BY-NC-SA
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The case , , gives , where . Substitute to get .
Since the leading coefficient of the equation is , a rational root would have to be an integer that divides 32. But no integer , , , , , , , , , is a root of the equation. Therefore the last equation in (and so also the first in ) has no rational solutions.
According to the theorem on p. 42 of [1], none of the roots can be constructed by ruler and compass, but the roots can be constructed using a marked ruler [1, p. 134].
Reference
[1] G. E. Martin, Geometric Constructions, New York: Springer, 1998.
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