11,000+
Interactive Demonstrations Powered by Notebook Technology »
TOPICS
LATEST
ABOUT
AUTHORING AREA
PARTICIPATE
Your browser does not support JavaScript or it may be disabled!
An Angle Bisection
Let ABC be a triangle and let A', B', and C' be the contact points of the incircle opposite A, B, and C, respectively. Let H be the foot of the perpendicular to A'C' from B'. Then B'H bisects
AHC.
Contributed by:
Jay Warendorff
After work by:
Antonio Gutierrez
THINGS TO TRY
Drag Locators
SNAPSHOTS
DETAILS
The statement of the theorem is in
Triangle: Incircle, Perpendicular, Angle Bisector
.
RELATED LINKS
Angle Bisector
(
Wolfram
MathWorld
)
Incircle
(
Wolfram
MathWorld
)
Perpendicular
(
Wolfram
MathWorld
)
PERMANENT CITATION
"
An Angle Bisection
" from
the Wolfram Demonstrations Project
http://demonstrations.wolfram.com/AnAngleBisection/
Contributed by:
Jay Warendorff
After work by:
Antonio Gutierrez
Share:
Embed Interactive Demonstration
New!
Just copy and paste this snippet of JavaScript code into your website or blog to put the live Demonstration on your site.
More details »
Download Demonstration as CDF »
Download Author Code »
(preview »)
Files require
Wolfram
CDF Player
or
Mathematica
.
Related Demonstrations
More by Author
A Congruent Angle inside the Incircle
Jay Warendorff
Intersecting Circles and a Right Angle
Jay Warendorff
A Concurrency Generated by the Angle Bisectors
Jay Warendorff
The Intersection of an Angle Bisector and a Perpendicular Bisector
Jay Warendorff
Division of an Angle Bisector by the Incenter
Jay Warendorff
Perpendiculars from a Point on the Line between the Endpoints of the Angle Bisectors
Jay Warendorff
Bisection of Segments by the Sides of a Triangle
Jay Warendorff
Angle Bisector Theorem
Jay Warendorff
Bisecting a Triangle
Jaime Rangel-Mondragon
Angle Bisectors in a Triangle
Jay Warendorff
Related Topics
Plane Geometry
Triangles
Browse all topics