# Forces on a Completely Submerged Gate

A gate hinged at the top is submerged under water. The gate is 2.5 meters long and 1 meter wide. This Demonstration calculates the force that must be applied to keep the gate closed. Use the sliders to set the water height and the gate weight. Check the "show distances" box to display distances.

### DETAILS

This Demonstration determines the magnitude of the applied force needed to keep a gate, which is meters wide and meters tall, closed (see Figure 1).
The magnitude of the resultant force is found by summing the differential forces over the gate surface:
,
where is the vertical distance from the water surface (m), is the coordinate (along the diagonal) from the water surface (m), is the resultant force (N), is the gate area (), is the width of the gate (m), is the length of the gate (m) as shown in Figure 1, is the angle (degrees) and is the specific weight of water ().
Solving the integral for :
,
where is the vertical distance from the fluid surface to the centroid of the gate (m) and is the coordinate of the gate centroid (m).
The coordinate of the resultant force can be found by summing moments around the hinge:
.
When is substituted into this equation, and the right side is integrated from to , then becomes:  .
A moment balance is done to determine the applied force that keeps the gate closed:
,
rearranging to solve for :
,
where is the weight of the gate (N), is the diagonal length from the hinge to the top of the water (m) and is the applied force (N).
Figure 1
Reference
[1] B. R. Munson, D. F. Young, T. H. Okiishi and W. W. Huebsch, Fundamentals of Fluid Mechanics, 6th ed., Hoboken, NJ: John Wiley and Sons, 2009 pp. 58–60.

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