Nine-Point Circle in the Complex Plane

Drag the sliders to explore triangles with vertices on the unit circle and their nine-point circles. Use the bookmark for right triangles, moving the slider.

SNAPSHOTS

  • [Snapshot]
  • [Snapshot]
  • [Snapshot]
  • [Snapshot]

DETAILS

Three points on the unit circle can be specified by their polar angles:
.
The vertices of triangle , then, are at the complex points
.
The midpoints (red) of the sides , , are simply
.
These three points define the nine-point circle, which has its center at
and radius . The formula for the nine-point circle is
.
The points (blue) for the intersections of the altitudes on the extended baselines {AB, AC, BC} are
.
The orthocenter (point O), which is the intersection of the extended altitudes of the triangle, is
.
The final three points (green) on the nine-point circle are the midpoints of the segments from the vertices to the orthocenter:
.
Thus we have a complete solution for the nine-point circle. From this discussion, it is apparent that there exist solutions for degenerate triangles where two or all of the points are the same, yielding a line segment or a point. To show the degenerate solutions, set two or all three of the sliders to the same value.
    • Share:

Embed Interactive Demonstration New!

Just copy and paste this snippet of JavaScript code into your website or blog to put the live Demonstration on your site. More details »

Files require Wolfram CDF Player or Mathematica.