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Products of Segments of Altitudes
Let ABC be a triangle, let AA', BB', and CC' be the altitudes, and let H be the orthocenter, the intersection of the altitudes. Then AH×HA' = BH×HB' = CH×HC'.
Contributed by:
Jay Warendorff
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Altitude
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Orthocenter
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PERMANENT CITATION
"
Products of Segments of Altitudes
" from
the Wolfram Demonstrations Project
http://demonstrations.wolfram.com/ProductsOfSegmentsOfAltitudes/
Contributed by:
Jay Warendorff
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