10854
EXPLORE
LATEST
ABOUT
AUTHORING AREA
PARTICIPATE
Your browser does not support JavaScript or it may be disabled!
Products of Segments of Altitudes
Let ABC be a triangle, let AA', BB', and CC' be the altitudes, and let H be the orthocenter, the intersection of the altitudes. Then AH×HA' = BH×HB' = CH×HC'.
Contributed by:
Jay Warendorff
THINGS TO TRY
Drag Locators
SNAPSHOTS
RELATED LINKS
Altitude
(
Wolfram
MathWorld
)
Orthocenter
(
Wolfram
MathWorld
)
PERMANENT CITATION
"
Products of Segments of Altitudes
" from
the Wolfram Demonstrations Project
http://demonstrations.wolfram.com/ProductsOfSegmentsOfAltitudes/
Contributed by:
Jay Warendorff
Share:
Embed Interactive Demonstration
New!
Just copy and paste this snippet of JavaScript code into your website or blog to put the live Demonstration on your site.
More details »
Download Demonstration as CDF »
Download Author Code »
(preview »)
Files require
Wolfram
CDF Player
or
Mathematica
.
Related Demonstrations
More by Author
Altitudes and Incircles
Jay Warendorff
Bisection of Segments by the Sides of a Triangle
Jay Warendorff
Triangle Altitudes and Circumradius
Jay Warendorff
Triangle Altitudes and Inradius
Jay Warendorff
The Product of an Altitude and the Circumradius of a Triangle
Jay Warendorff
Four Collinear Points Related to the Altitudes
Jay Warendorff
Projections, an Altitude, and the Orthocenter
Jay Warendorff
A Relation between Altitudes of Four Triangles
Jay Warendorff
Concyclic Points Derived from Midpoints of Altitudes
Jay Warendorff
The Incircle and the Altitudes of a Triangle
Jay Warendorff
Related Topics
Plane Geometry
Triangles
Browse all topics
Note: To run this Demonstration you need Mathematica 7+ or the free Mathematica Player 7EX
Download or upgrade to
Mathematica Player 7EX
I already have
Mathematica Player
or
Mathematica 7+