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Products of Segments of Altitudes

Let ABC be a triangle, let AA', BB', and CC' be the altitudes, and let H be the orthocenter, the intersection of the altitudes. Then AH×HA' = BH×HB' = CH×HC'.

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"Products of Segments of Altitudes" from the Wolfram Demonstrations Project
 http://demonstrations.wolfram.com/ProductsOfSegmentsOfAltitudes/
Contributed by: Jay Warendorff
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