Uniform Continuity

This Demonstration illustrates a theorem of analysis: a function that is continuous on the closed interval is uniformly continuous on the interval.
A function is continuous if, for each point and each positive number , there is a positive number such that whenever , . A function is uniformly continuous if, for each positive number , there is a positive number such that for all , whenever, . In the first case depends on both and ; in the second, depends only on .
 
Powered by Wolfram Mathematica
Give us your feedback
Give us your feedback

Source page:




 often  occasionally  never

Note: Please do not include anything you consider confidential or proprietary. Your message and contact information may be shared with the author of any specific Demonstration for which you give feedback, but will not otherwise be published or distributed.
Privacy Policy »

Note: To run this Demonstration you need the free
Mathematica Player
or Mathematica 7+
Download or upgrade to Mathematica Player 7
I already have Mathematica Player or Mathematica 7+