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Izidor Hafner
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Demonstrations 81  100 of 1036
Geometric Construction of the Square Roots of a Complex Number
Nicomedes's Geometric Construction of Principal Cube Root
Verging Using a Marked Ruler
11b. Construct a Triangle Given the Lengths of Two Sides and the Bisector of Their Common Angle
6. Construct a Triangle Given Its Circumradius, Inradius and the Length of Its Base
17b. Construct a Triangle Given the Length of an Angle Bisector, the Angle at Another Vertex and the Distance from the Third Vertex to the Angle Bisector
17a. Construct a Triangle Given the Length of an Angle Bisector, the Angle at Another Vertex and Distance from the Third Vertex to the Angle Bisector
16. Construct a Triangle Given Its Circumradius, Inradius and the Difference of Its Base Angles
15. Construct a Triangle Given the Lengths of Two Sides and the Median to the Third Side
14. Construct a Triangle Given the Length of the Altitude to the Base, a Base Angle and the Sum of the Lengths of the Other Two Sides
5. Construct a Triangle Given Its Circumradius, the Difference of Base Angles and the Sum of the Other Two Sides
12. Construct a Triangle Given the Length of Its Base, the Perimeter and the Difference of the Base Angles
4. Construct a Triangle Given Its Circumradius, Inradius and a Vertex Angle
3. Construct a Triangle Given the Length of an Altitude, the Inradius and the Difference of the Base Angles
11a. Construct a Triangle Given the Lengths of Two Sides and the Bisector of Their Included Angle
10. Construct a Triangle Given the Length of Its Base, the Difference of the Base Angles and the Slope of the Median to the Base
9. Construct a Triangle Given the Length of Its Base, the Difference of the Base Angles and the Sum of the Other Two Sides
8. Construct a Triangle Given the Lengths of Two Sides and the Length of the Altitude to One of Them
7. Construct a Triangle Given the Lengths of Two Sides and a Median of the Third Side
2. Construct a Triangle Given the Circumradius, the Difference of the Base Angles, with the Circumcenter on the Incircle
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