An Angle Bisection

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Let ABC be a triangle and let A', B', and C' be the contact points of the incircle opposite A, B, and C, respectively. Let H be the foot of the perpendicular to A'C' from B'. Then B'H bisects AHC.

Contributed by: Jay Warendorff (March 2011)
After work by: Antonio Gutierrez
Open content licensed under CC BY-NC-SA



The statement of the theorem is in Triangle: Incircle, Perpendicular, Angle Bisector.

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