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Let ABC be a triangle with circumcenter O. Let X, Y, and Z be the circumcenters of BOC, COA, and AOB, respectively. Then AX, BY, and CZ are concurrent. The point of concurrency K is called the Kosnita point.
Contributed by: Jay Warendorff (March 2011)
Open content licensed under CC BY-NC-SA
Wolfram Demonstrations Project
Published: March 7 2011