Perpendiculars to a Chord
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Let the chord CF intersect the diameter AB of a circle. Let D and E be the feet of the perpendiculars from A and B to CF. Then CD = EF.[more]
Drag the orange points to change the figure.[less]
Contributed by: Jay Warendorff (March 2011)
After work by: Antonio Gutierrez
Open content licensed under CC BY-NC-SA
The statement of the theorem is in Archimedes' Book of Lemmas: Proposition 13.
"Perpendiculars to a Chord"
Wolfram Demonstrations Project
Published: March 7 2011