### Description:

Given two equal-size strings s and t. In one step you can choose any character of t and replace it with another character.

Return the minimum number of steps to make t an anagram of s.

An Anagram of a string is a string that contains the same characters with a different (or the same) ordering.

### Solution:

Time Complexity : O(n)

Space Complexity: O(1)

```
var minSteps = function(s, t) {
// Array to hold the counts of each letter
const counts = new Array(26).fill(0);
// Add counts of each letter to the array
// zero = no difference, positive or negative count = count difference between the two strings for a particular
for (let i = 0; i < s.length; i++) {
counts[t.charCodeAt(i) - 97]++;
counts[s.charCodeAt(i) - 97]--;
}
let output = 0;
// Add the letter count differences together
for (let i = 0; i < 26; i++) {
if (counts[i] > 0) output += counts[i];
}
return output;
};
```

## Discussion (0)