The Plemelj Construction of a Triangle: 13
This Demonstration constructs a triangle given the length of its base , the length of the altitude from to and the difference between the angles and at and . This is not one of Plemelj's original constructions, but a new one based on his equation , where and . It is the same as The Plemelj Construction of a Triangle: 8, but the verification is different.[more]
The modified equation is .
Step 1: Draw a straight line of length and a line parallel to at distance . Let be the midpoint of , and let be the point on directly above . Let be the reflection of in .
Step 2: Draw a circle with center and radius .
Step 3: Draw the ray from at the angle from to intersect at the point .
Step 4: Draw the circle with center and radius .
Step 5: Measure out a point on the circle at distance from .
Step 6: The point is the intersection of and the right bisector of .
Step 7: The triangle meets the stated conditions.
Angle , so . But , since .
So . Since , .[less]
For the history of this problem, references and a photograph of Plemelj's first solution, see The Plemelj Construction of a Triangle: 1.