# Ceva's Theorem

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Let P be a point inside the triangle ABC. Draw lines from A, B and C through P to the points A', B', and C' on the opposite sides. Then AB'×BC'×CA' = AC'×BA'×CB'.

Contributed by: Jay Warendorff (March 2011)

Open content licensed under CC BY-NC-SA

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detailSectionParagraph## Permanent Citation

"Ceva's Theorem"

http://demonstrations.wolfram.com/CevasTheorem/

Wolfram Demonstrations Project

Published: March 7 2011