Let ABC be a triangle. Let a line intersect the sides of ABC (perhaps extended) at A', B', and C'. Then the midpoints of the segments AA', BB', and CC' are collinear.
THINGS TO TRY
See problem 6 in
Classical Theorems in Plane Geometry
the Wolfram Demonstrations Project
Embed Interactive Demonstration
More details »
Download Demonstration as CDF »
Download Author Code »
More by Author
A Line Associated with an Excircle
A Line Parallel to a Side of a Triangle
Concurrent Lines that Intersect on the Euler Line
Bisecting a Line Segment through the Orthocenter
Intersection of an Altitude and a Line through the Incenter
A Concurrency from the Midpoints of Line Segments through the Circumcenter
Dividing a Triangle by Lines Parallel to Two Sides
Lines Parallel to the Sides of a Triangle
Subtriangles Formed by Concurrent Lines Parallel to the Sides of a Triangle
Browse all topics
The #1 tool for creating Demonstrations
and anything technical.
Explore anything with the first
computational knowledge engine.
The web's most extensive
Course Assistant Apps »
An app for every course—
right in the palm of your hand.
Wolfram Blog »
Read our views on math,
science, and technology.
Computable Document Format »
The format that makes Demonstrations
(and any information) easy to share and interact with.
STEM Initiative »
Programs & resources for
educators, schools & students.
Join the initiative for modernizing
Note: Your message & contact information may be shared with the author of any specific Demonstration for which you give feedback.
© 2014 Wolfram Demonstrations Project & Contributors |
Note: To run this Demonstration you need Mathematica 7+ or the free Mathematica Player 7EX
Download or upgrade to
Mathematica Player 7EX
I already have