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Perpendiculars from a Point on the Line between the Endpoints of the Angle Bisectors


	Let ABC be a triangle. Let AA' and BB' bisect the angles CAB and ABC. Let P be a point on A'B' and PQ be perpendicular to AB. Let PB'' and PA'' be perpendicular to AC and BC. Then PQ = PA'' + PB''.


	Contributed by: Jay Warendorff

See problem 1.13 in V. Prasolov, Problems in Plane and Solid Geometry, Vol. 1, Plane Geometry [PDF], (D. Leites, ed. and trans.).

Angle Bisector (Wolfram MathWorld)

Perpendicular (Wolfram MathWorld)

"Perpendiculars from a Point on the Line between the Endpoints of the Angle Bisectors" from The Wolfram Demonstrations Project
http://demonstrations.wolfram.com/PerpendicularsFromAPointOnTheLineBetweenTheEndpointsOfTheAng/

Contributed by: Jay Warendorff

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