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Perpendiculars to a Chord
Let the chord CF intersect the diameter AB of a circle. Let D and E be the feet of the perpendiculars from A and B to CF. Then CD = EF.
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Contributed by:
Jay Warendorff
After work by:
Antonio Gutierrez
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The statement of the theorem is in
Archimedes' Book of Lemmas: Proposition 13
.
RELATED LINKS
Chord
(
Wolfram
MathWorld
)
Perpendicular
(
Wolfram
MathWorld
)
PERMANENT CITATION
"
Perpendiculars to a Chord
" from
the Wolfram Demonstrations Project
http://demonstrations.wolfram.com/PerpendicularsToAChord/
Contributed by:
Jay Warendorff
After work by:
Antonio Gutierrez
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