Perpendiculars to a Chord

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Let the chord CF intersect the diameter AB of a circle. Let D and E be the feet of the perpendiculars from A and B to CF. Then CD = EF.

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Contributed by: Jay Warendorff (March 2011)
After work by: Antonio Gutierrez
Open content licensed under CC BY-NC-SA


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The statement of the theorem is in Archimedes' Book of Lemmas: Proposition 13.



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