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Perpendiculars to a Chord


	Let the chord CF intersect the diameter AB of a circle. Let D and E be the feet of the perpendiculars from A and B to CF. Then CD = EF. Drag the orange points to change the figure.


	Contributed by: Jay Warendorff After work by: Antonio Gutierrez

The statement of the theorem is in Archimedes' Book of Lemmas: Proposition 13.

Chord (Wolfram MathWorld)

Perpendicular (Wolfram MathWorld)

"Perpendiculars to a Chord" from The Wolfram Demonstrations Project
http://demonstrations.wolfram.com/PerpendicularsToAChord/

Contributed by: Jay Warendorff

After work by: Antonio Gutierrez

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