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A Lemma of Archimedes about a Bisected Segment
Let AB be the diameter of a semicircle. Let CB and CD be tangents. If DE is perpendicular to AB and DE intersects AC at F then DF = FE.
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Contributed by:
Jay Warendorff
After work by:
Antonio Gutierrez
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The statement of the theorem is in
Archimedes' Book of Lemmas: Proposition 2
.
RELATED LINKS
Circle Tangent Line
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Perpendicular
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"
A Lemma of Archimedes about a Bisected Segment
" from
the Wolfram Demonstrations Project
http://demonstrations.wolfram.com/ALemmaOfArchimedesAboutABisectedSegment/
Contributed by:
Jay Warendorff
After work by:
Antonio Gutierrez
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