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Let O be the circumcenter of the triangle ABC. Let the line perpendicular to AO at O intersect AB and AC at M and N. Let the intersection of MC and NB be K. Let H and P be the orthocenters of ABC and AMN, respectively. Then H, P, and K are collinear.
Contributed by: Jay Warendorff (March 2011)
Open content licensed under CC BY-NC-SA
Wolfram Demonstrations Project
Published: March 7 2011