Another Variant of Kosnita's Theorem

Initializing live version

Let ABC be a triangle with incenter I. Let X, Y, and Z be the incenters of BIC, CIA, and AIB, respectively. Then AX, BY, and CZ are concurrent.

Contributed by: Jay Warendorff (August 2008)
After work by: Michael de Villiers
Open content licensed under CC BY-NC-SA

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