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The Circumcircle of the Orthocenter and Two Vertices and a Parallelogram

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Let ABC be a triangle. Let the perpendicular from the orthocenter H to the altitude HC intersect the circumcircle of HBC at P. Then ABPH is a parallelogram.

Contributed by: Jay Warendorff (March 2011)
Open content licensed under CC BY-NC-SA

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