Points Symmetric to the Orthocenter with Respect to the Sides of a Triangle

Let ABC be a triangle. The points A', B', and C' symmetric to the orthocenter H with respect to the sides of ABC lie on the circumcircle. (A'', B'', and C'' are the feet of the perpendiculars from H to BC, CA, and AB, respectively.)


See problem 5.9 in V. Prasolov, Problems in Plane and Solid Geometry, Vol. 1, Plane Geometry [PDF], (D. Leites, ed. and trans.).
comments
 
Powered by Wolfram Mathematica
Give us your feedback
Give us your feedback

Source page:




 often  occasionally  never

Note: Please do not include anything you consider confidential or proprietary. Your message and contact information may be shared with the author of any specific Demonstration for which you give feedback, but will not otherwise be published or distributed.
Privacy Policy »

Note: To run this Demonstration you need the free
Mathematica Player
or Mathematica 7+
Download or upgrade to Mathematica Player 7
I already have Mathematica Player or Mathematica 7+