The Triangle Formed by the Centers of the Miquel Circles

Let ABC be a triangle. Let A', B', and C' be points on BC, AC, and AB, respectively. Let A'', B'', and C'' be the circumcenters of AB'C', BA'C', and CA'B', respectively. Then A"B''C'' is similar to ABC.

THINGS TO TRY

SNAPSHOTS

  • [Snapshot]
  • [Snapshot]
  • [Snapshot]

DETAILS

See problem 12 in D. R. Davis, Modern College Geometry, Cambridge, MA: Addison-Wesley Press, 1949 p. 161.
    • Share:

Embed Interactive Demonstration New!

Just copy and paste this snippet of JavaScript code into your website or blog to put the live Demonstration on your site. More details »

Files require Wolfram CDF Player or Mathematica.