# Division of an Angle Bisector by the Incenter

Requires a Wolfram Notebook System

Interact on desktop, mobile and cloud with the free Wolfram Player or other Wolfram Language products.

Let ABC be a triangle with incenter I. Let AA' be the bisector of with A' on BC. Then .

Contributed by: Jay Warendorff (March 2011)

Open content licensed under CC BY-NC-SA

## Snapshots

## Details

Problem 1.17(b) in V. Prasolov, *Problems in Plane and Solid Geometry*, Vol. 1, *Plane Geometry* [PDF], (D. Leites, ed. and trans.).

## Permanent Citation

"Division of an Angle Bisector by the Incenter"

http://demonstrations.wolfram.com/DivisionOfAnAngleBisectorByTheIncenter/

Wolfram Demonstrations Project

Published: March 7 2011