9814

Exploring Surface Curvature and Differentials

This Demonstration shows the relationship between the principal curvatures of a surface and the differential of the unit normal of the surface. The differential at a point may be viewed as a linear transformation of the tangent plane at the point, since the derivative of the unit normal is orthogonal to the normal. The eigenvalues of are the negatives of the principal curvatures of the surface at the point, and correspondingly the eigenvectors are the principal directions. At a point one may rotate an orthogonal basis for the tangent plane to diagonalize the matrix for by aligning the basis with the principal directions. One may see how a small tangent vector is mapped by and compare it to the actual difference in the normals at the points and . The lines that are drawn on the surface are lines of curvature, which are curves whose tangents at every point match one of the principal directions.

SNAPSHOTS

  • [Snapshot]
  • [Snapshot]
  • [Snapshot]

DETAILS

In addition to the principal curvatures of a surface, this Demonstration illustrates geometrically several interesting concepts: differentials and local linear approximation, linear transformations, eigenvectors and eigenvalues, the orthogonal diagonalization of symmetric matrices, and the relation of the rotation of the normal vector of a surface to the curvature. Note the negative of is called the shape operator.
To explore as a linear transformation: move to a desired location. Move to change the tangent vector at ; the motion of may be constrained to move horizontally or vertically. The image vector is drawn in the plane at the end of the normal at . The image plane may be drawn with the same basis as the tangent plane (the "reference" grid) or with the image of the basis under (the "image" grid). The basis of the tangent plane may be rotated with the slider. By rotating the basis to align with the principal directions, the matrix of may be diagonalized. In the display, numerical values of , , and are given with respect to the basis of the tangent plane.
The display: the lines on the surface show the principal configuration (lines of curvature). At the point , the unit normal vector is drawn in black, and the lines of curvature through are drawn on the surface. For the point , the normal is drawn twice in green, both at and at . There are two things to observe: the angle between the normals and the displacement between the tips of the normals. On the one hand, if the change is parallel to a principal direction, then the angle rotated will be approximately the negative of the curvature times the distance moved; on the other hand, the displacement will be approximately equal to . Basis vectors are highlighted in the tangent plane and the image grid.
Umbilic points are points where the normal curvature is the same in all directions and is scalar. Some of them are bookmarked in the + menu in the upper left. Darboux first classified curvature umbilics into three types, now sometimes called lemons, stars, and monstars (or lemonstars). For more information, see G. Darboux, "Note VII: Sur la forme des lignes de courbure dans la voisinage d'un ombilic," Leçons sur la Théorie Générale des Surfaces, Vol. 4, Paris: Gauthier–Villars, 1896 pp. 448–465.
Questions for exploration:
When the matrix of is diagonalized, the image grid is a rectangle. Why?
When the vector is rotated, which way does its image rotate? When is it in the same direction and when is it different? Is it ever the case that the image of does not rotate but changes length?
Sometimes the tip of the image vector stays close to the tip of the green normal based at , and sometimes it does not. Why? To clarify: since the normal vectors are unit length, the green vector rotates away from the plane. One expects the tips to lie on a line approximately parallel to the normal. In other words, if the viewpoint is adjusted so the reference grids align, one tip should be on top of the other. Sometimes they are closer, and sometimes not.
Is it obvious—in the visual sense—that the principal curvatures and the eigenvalues of have opposite signs?
Show that if traces the unit circle in the tangent plane, the coordinates being with respect to the orthonormal basis of principal directions, then its image traces the ellipse , where and are the principal curvatures. Deduce Euler's formula for the normal curvature in the direction , namely, .
    • Share:

Embed Interactive Demonstration New!

Just copy and paste this snippet of JavaScript code into your website or blog to put the live Demonstration on your site. More details »

Files require Wolfram CDF Player or Mathematica.









 
RELATED RESOURCES
Mathematica »
The #1 tool for creating Demonstrations
and anything technical.
Wolfram|Alpha »
Explore anything with the first
computational knowledge engine.
MathWorld »
The web's most extensive
mathematics resource.
Course Assistant Apps »
An app for every course—
right in the palm of your hand.
Wolfram Blog »
Read our views on math,
science, and technology.
Computable Document Format »
The format that makes Demonstrations
(and any information) easy to share and
interact with.
STEM Initiative »
Programs & resources for
educators, schools & students.
Computerbasedmath.org »
Join the initiative for modernizing
math education.
Step-by-step Solutions »
Walk through homework problems one step at a time, with hints to help along the way.
Wolfram Problem Generator »
Unlimited random practice problems and answers with built-in Step-by-step solutions. Practice online or make a printable study sheet.
Wolfram Language »
Knowledge-based programming for everyone.
Powered by Wolfram Mathematica © 2014 Wolfram Demonstrations Project & Contributors  |  Terms of Use  |  Privacy Policy  |  RSS Give us your feedback
Note: To run this Demonstration you need Mathematica 7+ or the free Mathematica Player 7EX
Download or upgrade to Mathematica Player 7EX
I already have Mathematica Player or Mathematica 7+